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#include <iostream>
#include "mem/ruby/slicc_interface/RubyRequest.hh"
using namespace std;
void
RubyRequest::print(ostream& out) const
{
out << "[RubyRequest: ";
out << "LineAddress = " << m_LineAddress << " ";
out << "PhysicalAddress = " << m_PhysicalAddress << " ";
out << "Type = " << m_Type << " ";
out << "ProgramCounter = " << m_ProgramCounter << " ";
out << "AccessMode = " << m_AccessMode << " ";
out << "Size = " << m_Size << " ";
out << "Prefetch = " << m_Prefetch << " ";
// out << "Time = " << getTime() << " ";
out << "]";
}
bool
RubyRequest::functionalRead(Packet *pkt)
{
// This needs a little explanation. Initially I thought that this
// message should be read. But the way the memtester works for now,
// we should not be reading this message as memtester updates the
// functional memory only after a write has actually taken place.
return false;
}
bool
RubyRequest::functionalWrite(Packet *pkt)
{
// This needs a little explanation. I am not sure if this message
// should be written. Essentially the question is how are writes
// ordered. I am assuming that if a functional write is issued after
// a timing write to the same address, then the functional write
// has to overwrite the data for the timing request, even if the
// timing request has still not been ordered globally.
Address pktLineAddr(pkt->getAddr());
pktLineAddr.makeLineAddress();
if (pktLineAddr == m_LineAddress) {
uint8_t *pktData = pkt->getPtr<uint8_t>(true);
unsigned int size_in_bytes = pkt->getSize();
unsigned startByte = pkt->getAddr() - m_LineAddress.getAddress();
for (unsigned i = 0; i < size_in_bytes; ++i) {
data[i + startByte] = pktData[i];
}
return true;
}
return false;
}
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